907. 子数组的最小值之和

907. 子数组的最小值之和

解法一: 单调栈

go
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func sumSubarrayMins(arr []int) int {
n := len(arr)
leftArr := make([]int, n)
queue := []int{}
for i, num := range arr {
for len(queue) > 0 && arr[queue[len(queue) - 1]] > num {
queue = queue[:len(queue) - 1]
}
if len(queue) == 0 {
leftArr[i] = -1
} else {
leftArr[i] = queue[len(queue) - 1]
}
queue = append(queue, i)
}
rightArr := make([]int, n)
queue = []int{}
for i := n - 1; i >= 0; i-- {
num := arr[i]
for len(queue) > 0 && arr[queue[len(queue) - 1]] >= num {
queue = queue[:len(queue) - 1]
}
if len(queue) == 0 {
rightArr[i] = n
} else {
rightArr[i] = queue[len(queue) - 1]
}
queue = append(queue, i)
}
ans := 0
const MOD = 1000000007
for i, num := range arr {
ans = (ans + num * (i - leftArr[i]) * (rightArr[i] - i)) % MOD
}
return ans
}
作者

wuhunyu

发布于

2023-11-27

更新于

2023-11-27

许可协议